# CICADA 3301 2014 PUZZLE FACTS PART 9

*144*pages on

this wiki

## A Life Sign

On May 2nd, 2014 at around 10:00 GMT, 3301 sent out messages to all of the hidden services previously registered on Onion 6. The requests made on the hidden services looked like this:

127.0.0.1 - - [02/May/2014:10:**:** +0200] "GET /key.asc HTTP/1.1" 200 * "-" "Cicada/33.01 CicaDOS 1.033 E Edition"PP 127.0.0.1 - - [02/May/2014:10:**:** +0200] "GET / HTTP/1.1" 200 * "-" "Cicada/33.01 CicaDOS 1.033 E Edition" 127.0.0.1 - - [02/May/2014:11:**:** +0200] "POST /cgi-bin/upload HTTP/1.1" 200 * "-" "Cicada/33.01 Cic/DOS/ 1.033 S Edition"

They requested the public key and and the root before uploading a file named message.txt.asc to the hidden service. The file contained a valid signature and a link to a new onion (ky2khlqdf7qdznac.onion). As it appears, the emails sent to different people were identical.

The GET request was made by Cicados 'E Edition' and the POST by 'S Edition', E and S are the 5th and 19th letters in the alphabet, with S being 7th letter from the end of the alphabet ie 5 and 7.

The message.asc.txt file is malformed with non-visble ascii spaces in the message that provide a hint in the form of the prime number sequence with the digit 19 missing.

Linked below is a screenshot of the message.asc.txt file so you can see how the numbers are encoded:

In July 2015, a similar sequence of spaces was found within the PGP signed pastebin message that was published from the Cicada twitter account (https://twitter.com/1231507051321). This sequence can be seen here:

Further discussion on the possible significance of these spaces can be found here:

Cicada Breaks the Silence: 2015 Twitter Message

## Onion 7 - ky2khlqdf7qdznac.onion

The onion from the message was running a thttpd server, version 2.25b. It was modified on April 2nd 08:33:19 GMT, meaning it took 3301 one month to set the website up and they let us wait another month before finally uploading a message.

Header:

Server: thttpd/2.25b 29dec2003 Last-Modified: Wed, 02 Apr 2014 08:33:19 GMT Date: Fri, 02 May 2014 11:32:45 GMT Content-Type: text/html; charset=iso-8859-1 Connection: close Accept-Ranges: bytes

Requesting a non existent file resulted in a 404 page giving the port used by the server:

Apache Server at 127.0.0.1 Port 5243

Trying to connect to the server with telnet resulted in the following error:

UNKNOWN 400 BaO'[d Request Server: thttpd/2.25b 29dec2003 Content-Type: text/html; charset=iso-8859-1 Date: Fri, 02 May 2014 11:46:39 GMT Last-Modified: Fri, 02 May 2014 11:46:39 GMT Accept-Ranges: bytes Connection: close Cache-Control: no-cache,no-store <HTML> <HEAD><TITLE>400 Bad Request</TITLE></HEAD>

<BODY BGCOLOR="#cc9999" TEXT="#000000" LINK="#2020ff" VLINK="#4040cc">

< H2>400 Bad Request< /H2> Your request has bad syntax or is inherently impossible to satisfy. < HR> <ADDRESS><A HREF="http://www.acme.com/software/thttpd/">thttpd/2.25b 29dec2003</A></ADDRESS>

</BODY>

</HTML>

Source code:

< html > < head >< title >133</ title ></ head > < body > < div id="331" > < img src="0.jpg" />< br /> < img src="1.jpg" />< br /> < img src="2.jpg" />< br /> < img src="3.jpg" />< br /> < img src="4.jpg" />< br /> < img src="5.jpg" />< br /> < img src="6.jpg" />< br /> < img src="7.jpg" />< br /> < img src="8.jpg" />< br /> < img src="9.jpg" />< br /> < img src="10.jpg" />< br /> < img src="11.jpg" />< br /> < img src="12.jpg" />< br /> < img src="13.jpg" />< br /> < img src="14.jpg" />< br /> < img src="15.jpg" />< br /> < img src="16.jpg" />< br /> < img src="17.jpg" />< br /> < img src="18.jpg" />< br /> < img src="19.jpg" />< br /> < img src="20.jpg" />< br /> < img src="21.jpg" />< br /> < img src="22.jpg" />< br /> < img src="23.jpg" />< br /> < img src="24.jpg" />< br /> < img src="25.jpg" />< br /> < img src="26.jpg" />< br /> < img src="27.jpg" />< br /> < img src="28.jpg" />< br /> < img src="29.jpg" />< br /> < img src="30.jpg" />< br /> < img src="31.jpg" />< br /> < img src="32.jpg" />< br /> < img src="33.jpg" />< br /> < img src="34.jpg" />< br /> < img src="35.jpg" />< br /> < img src="36.jpg" />< br /> < img src="37.jpg" />< br /> < img src="38.jpg" />< br /> < img src="39.jpg" />< br /> < img src="40.jpg" />< br /> < img src="41.jpg" />< br /> < img src="42.jpg" />< br /> < img src="43.jpg" />< br /> < img src="44.jpg" />< br /> < img src="45.jpg" />< br /> < img src="46.jpg" />< br /> < img src="47.jpg" />< br /> < img src="48.jpg" />< br /> < img src="49.jpg" />< br /> < img src="50.jpg" />< br /> < img src="51.jpg" />< br /> < img src="52.jpg" />< br /> < img src="53.jpg" />< br /> < img src="54.jpg" />< br /> < img src="55.jpg" />< br /> < img src="56.jpg" />< br /> < img src="57.jpg" />< br /> </ div > </ body > </ html >

The onion contained 58 pages, numbered 0.jpg to 57.jpg, all written in runes and apparently part of the Liber Primus:

## Rune Pages, HTML File and message.txt.asc

A drop box of all unmodified files is available here:

http://tinyurl.com/2014onion7.

## Rune Page Sets

The rune pages appear to be in sets of various length as defined by decorations in their margins and a discussion on their meanings can be found here: http://archive.4plebs.org/x/thread/14547165/

Several of these symbols are repeated on pages of the Liber Primus received earlier but are reversed (ie the cicada emerging and the reclining man). Some symbols repeat across the page sets and are also similarly transformed by rotation or mirroring (ie the 5 dots and infinity or mobius symbol):

34.jpg to 39.jpg - cuneiform numbers, the Babylonians, sexagesimal numeral system, possible hint to base 60

7.jpg, 23.jpg and 56.jpg - 5 dots in various transformations

24.jpg to 26.jpg, 57.jpg, 14.jpg - Mayflies, Ephemeridae, possible hint to ephemeral cipher

8.jpg to 14.jpg, 32.jpg and 55.jpg - Dendrites in various forms, inverted

It is likely the decorations provide an indication of how to decode the pages within a set or provide a path through the different page sets. This hypothesis is reinforced by adjusting colour levels on the images to reveal what appears to be further information:

## Transcription of Runes

*Transcription is currently in progress and can be found here.*

**You can find the latest transcript here.**

A **numerical transcript** is available here: https://raw.githubusercontent.com/remlong/cicada-runes/gh-pages/runes.txt . The runes were numbered 0-28. Each page is on a new line and all spaces and symbols are underscores.

There are some scripts to decrypt runes based in some rules:

**runes.py** http://git.io/xQrlUg

**runescript.py** http://pastebin.com/zXMgSFLM (which is based in runes.py)

or a **tool** made by *_{elbarto@reborn.com}* that gives you all the matches from a dictionary (ask personally to him)

## Frequency findings

Pages 0-55 when considered as pairs the runes are not random. The link below shows a table where you can see the diagonal has less pairs than the other combos.

The pairs in the diagonal are listed below:

4,2,5,4,2,1,8,8,2,5,3,4,3,2,8,3,2,0,6,2,4,4,4,1,10,3,3

29 digits. The sum of the digits equal 109. Prime. 109 is the 29th prime. It is a twin prime to 107 and a Centered Triangular Number.

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

the above is incorrect

http://flourlicker.tumblr.com/post/113378458900/correct-grid

here is a corrected grid

## Rune Counts

Pages 0 to 57 Total Rune Count = 13,136

The number 13,136 is a Magnanimous number. If you insert a + between any digit then add, the sum will equal a prime number.

All of the possible primes:

1+3136 = 3137

13+136 = 149

131+36 = 167

1313+6 = 1319

The sums of the digits of these numbers: 13136; 3137; 149; 167; 1319 all equal 14 = 5.

An interesting side note: If you add up all of the page numbers (0 to 57) you get 1653. 1653 is the 57th Triangular number.

## Page 15

A discussion of the matrix on page 15 can be found here:

http://uncovering-cicada.wikia.com/wiki/Onion_7:_numbers_on_page_15

## Page 33 to 39

Page 33 to 39 contain a hint in the form of cuneiform which represents the numbers '17' '13' '55' and '1'. In base 60: 17*60+13 = 1033 and 55*60+1 = 3301

In the calculation of the cuneiform symbols 17*60 + 13=1033. 17 and 13 are not only prime BUT are the year intervals in which batches of cicadas emerge.

1033 and 3301 are also Hypotenuses for the Primitive Pythagoreen Triples (192, 1015, 1033) (1501, 2940, 3301). A Bablyon tablet (Plimpton 322) was found that was a list of triplets.

## Page 49, 50, 51

These pages contain the following ASCII text:

3N 3p 2l 36 1b 3v 26 33 1W 49 2a 3g 47 04 33 3W 21 3M 0F 0X 1g 2H 0x 1R 1n 3I 2r 0P 2U 16 2L 2D 1t 1s 3H 0d 0s 1K 2D 05 1K 1O 0S 1D 3o 1l 3J 1G 4D 0G 0l 0x 1Q 2p 2a 1K 4E 1w 2Q 19 1k 3G 24 0p 22 4F 0P 3C 3J 1D 2n 1m 2i 1J 3P 2v 1s 2O 0k 1M 2M 0w 3L 3D 2r 0S 1p 15 3V 3e 3I 0n 3u 1O 0u 0Z 3g 2U 1C 0Y 1N 3n 0W 3Q 22 13 0V 3c 0E 34 0W 1t 1D 2N 3H 47 0s 2p 0Z 34 0g 3v 1Q 0s 0D 0K 2h 3D 3L 2x 1Q 20 2n 2L 1C 2p 0A 29 3r 0D 45 0k 2e 2W 25 3U 1W 2r 46 2s 2X 39 3p 0X 0E 1q 0q 4B 49 48 3r 3b 3C 1M 1j 0I 4A 48 40 3m 4E 0s 2S 1v 3T 0I 3t 2B 2k 2t 2O 0e 2l 1L 28 2a 0J 1L 0c 3C 2o 0X 00 2Z 2d 1T 2u 1t 1j 0l 1o 1E 3T 18 3E 1G 27 0L 0v 2t 06 11 1A 2U 4B 1O 2M 3d 2S 0x 0w 0q 0p 2V 18 0q 1D 49 2O 00 1v 2t 1k 3s 3G 21 3w 0W 29 2r 2O 2L 0g 3Y 0M 0u 3I 3C 1r 2c 2q 3o 30 0a 39 1K

The first digit is always '0', '1', '2' or '3'. The last letter falls within '[0-9A-Za-x]', exactly 60 values. The maximum value is '4F'. This suggests a sexagesimal (base 60) counting system, where '4F' would correspond to '255'. The text can be rewritten in hexadecimal as follows:

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

The above does ignore the fact that there is also no 'f' letter in the text. Means that it could also be in base 59.

### Page 49

Page 49 contains:

3N 3p 2l 36 1b 3v 26 33 1W 49 2a 3g 47 04 33 3W 21 3M 0F 0X 1g 2H 0x 1R 1n 3I 2r 0P 2U 16 2L 2D 1t 1s 3H 0d 0s 1K 2D 05 1K 1O 0S 1D 3o 1l 3J 1G 4D 0G 0l 0x 1Q 2p 2a 1K 4E 1w 2Q 19 1k 3G 24 0p 22 4F 0P 3C 3J 1D 2n 1m 2i 1J 3P 2v 1s 2O 0k 1M

### Page 50

Page 50 contains:

2M 0w 3L 3D 2r 0S 1p 15 3V 3e 3I 0n 3u 1O 0u 0Z 3g 2U 1C 0Y 1N 3n 0W 3Q 22 13 0V 3c 0E 34 0W 1t 1D 2N 3H 47 0s 2p 0Z 34 0g 3v 1Q 0s 0D 0K 2h 3D 3L 2x 1Q 20 2n 2L 1C 2p 0A 29 3r 0D 45 0k 2e 2W 25 3U 1W 2r 46 2s 2X 39 3p 0X 0E 1q 0q 4B 49 48 3r 3b 3C 1M 1j 0I 4A 48 40 3m 4E 0s 2S 1v 3T 0I 3t 2B 2k 2t 2O 0e 2l 1L

### Page 51

Page 51 contains:

28 2a 0J 1L 0c 3C 2o 0X 00 2Z 2d 1T 2u 1t 1j 0l 1o 1E 3T 18 3E 1G 27 0L 0v 2t 06 11 1A 2U 4B 1O 2M 3d 2S 0x 0w 0q 0p 2V 18 0q 1D 49 2O 00 1v 2t 1k 3s 3G 21 3w 0W 29 2r 2O 2L 0g 3Y 0M 0u 3I 3C 1r 2c 2q 3o 30 0a 39 1K

***ANALYSIS OF HEXADECIMAL NUMBERS**

I have been messing around with the supposed hexadecimal numbers on these pages and this is what I have found:

There are 256, two-character units listed on these pages. Conversion from hexadecimal to base-10 will give you a range of numbers from 0 - 255.

If you add all 256 numbers together in base-10, you get 32987 -- this is a prime number!

*Now these previous points were simple enough to find out; the rest of what I did seemed legit, but no one else has posted it. Since everyone has been looking for prime numbers, I thought "Hey, what if in this situation the non-prime numbers were the key to solving it." So here you guys go:

The number of primes in this 256 set is 45. 256 - 45 = 211 -- this is a prime number!

Most of these 45 primes are repeats, the actual number of primes not counting repeats is 15. 256 - 15 = 241 -- this is a prime number!

The number of composite numbers, without repeats: 131 -- this is a prime number!

The number of numbers 0 - 255 not represented in the data set is 95. Out of those, the number of primes not represented is 24. 95 - 24 = 71 -- this is a prime number!

The summation of the numbers not represented is 11542. The summation of the primes not represented is 2355. If you subtract these numbers you get 9187 -- you guessed it, this is a prime number!

Now I've been messing with these pages for the last few months when I heard about the puzzle, I don't know if any one else has found out about this/ if it is any help at all, but these primes in my opinion cannot be a coincidence. I have really spent too much time on this puzzle, so I hope this will help. Best of luck!

*- LJ*

## Page 56

Shift the runes with a stream of (prime numbers, modulo 29) -1 ie 1,2,4,6,10,12,16,18,22,28,1,7,11,13.....Modulo 29 is used because there are 29 runes in the gematria so you only need the remainder of (Prime-1)/29 to determine and simplify the shift.

Page 56 decodes to:

AN END: WITHIN THE DEEP WEB TH ERE EXISTS A PAGE THAT HA SHES TO: 36367763ab73783c7af284446c 59466b4cd653239a311cb7116 d4618dee09a8425893dc7500b 464fdaf1672d7bef5e891c6e227 4568926a49fb4f45132c2a8b4 IT IS THE DUTY OF EUERY PILGR IM TO SEEK OUT THIS PAGE.

This could be interpreted as the hash of an onion page, however it should be noted that hashes can be used as unique file identifiers for deep web applications such as Freenet, Gnunet or P2P file sharing systems.

**Possibly an Important Note:** On Page __56__, the __57th__ rune (if counting from 1; 56th if counting from 0), an "__F__" rune, is skipped over. It is the __fourth__ of __five__ "F" runes on the page and the only one that is not encrypted. If you do not skip it, the prime number __269__ would be used (269 Mod 29)-1 = 7. This would result in "OE" instead of "F" and garbled text for the rest of the message. So 269 is not used here, and instead the next rune is shifted using prime number 269.

(Note: Could the garbled text be an input for another cipher? As in could it translate into something in sexagesimal, hex, gematria or others? - Hunter)

**Possible interpretation of the 5 dots at the bottom of this page as musical notes:**

**https://d2dfiiedkilzm4.cloudfront.net/res/InfoGraphic/Shostakovich-Cryptogram-Infographic.pdf**

Musical notes:

BFFDG = 171 (Gematria value)

HFFDG = 133 (German translation B=H. See link above)

Ti Fa Fa Re Sol = 499 (Solfege)

**CONNECTIONS WITH PI USING **☀http://www.angio.net/pi/

search for 3301: text value = h b [HFFDG = 133 (German translation B=H. See link above)] H=B

search for 499 (Ti Fa Fa Re Sol): Occurs at position 761 (The Instar Emergence)

search for 761: position 3547=prime

search for 57: position 404 (not found) with text value F -> The F is the 57th rune on the page and is skipped over (see above)

**Changing The numbers Around:**

** I took the numbers and wrote them down in rows, the numbers i got are:**

35d44 |
---|

Hope this Helps...

(Other author...)

I put those into a hexadecimal translator and got these outputs:

33 35 64 34 34 0d 0a 36 39 34 36 35 0d 0a 33 34 36 34 36 0d 0a 36 36 31 66 38 0d 0a 37 36 38 64 39 0d 0a 37 62 64 61 32 0d 0a 36 34 65 66 36 0d 0a 33 63 65 31 61 0d 0a 61 64 30 36 34 0d 0a 62 36 39 37 39 0d 0a 37 35 61 32 66 0d 0a 33 33 38 64 62 0d 0a 37 32 34 37 34 0d 0a 38 33 32 62 66 0d 0a 33 39 35 65 34 0d 0a 63 61 38 66 35 0d 0a 37 33 39 35 31 0d 0a 61 31 33 65 33 0d 0a 66 31 64 38 32 0d 0a 32 63 63 39 63 0d 0a 38 62 37 31 32 0d 0a 34 37 35 63 61 0d 0a 34 31 30 36 38 0d 0a 34 31 30 65 62 0d 0a 36 36 62 32 34 0d 0a 32 20 20 32 0d 0a 37

I hope this can help.

## Page 57

Page 57 is not encrypted and can be decoded directly from the Gematria Primus:

Parable : like the instar tunneling to the surface. We must shed our own circumferences. Find the divinity within and emerge.

This is Parable 1,595,277,641 which appeared in 2013 within the ID tag of 761.mp3. The mp3 title is 'The Instar Emergence' which can be summed using the Gematria Primus to obtain '761'. The number 1,595,277,641 is similarly obtained using the product of the gematria sums of each line of the parable ie 1259*1031*1229 = 1,595,277,641.

Interesting observation speaking of circumferences:

Way back on Onion 1, the Blake Collage.

http://uncovering-cicada.wikia.com/wiki/DEBATE_ABOUT_MEANING_OF_THE_PICTURE_ON_ONION

It was thought that 1033 was written in roman numerals at the end of the pointing finger.

1 + 0 + 3 + 3 = 7, so if the center point of the circle is 7, lets say we can assume the diameter is 14. The circumference would be 43.982... If we drop all digits after the decimal (because Babylonians didn't use decimals) then we get 43.

43 is prime and the 14th prime. The sum of the digits is 7.

If you spell 43 as Fourty three, rather than Forty three, then two Gematria values are possible because of the TH in three.

(T & H) = 2 + 7 + 3 + 11 + 59 + 103 + (59 + 23) + 11 + 67 + 67 = 412 = 4 + 1 + 2 = 7

(TH) = 2 + 7 + 3 + 11 + 59 + 103 + (5) + 11 + 67 + 67 = 335 = 3 + 3 + 5 = 11 prime

The funny thing is 11 is called A Pointer prime and the finger in the painting is pointing at 1033. :)

## A Rough Summary of the 2014 Cicada 3301 Puzzle So Far

Available here: http://pastebin.com/9LZbJeB5

I went through this wiki and the cicada puzzles wiki to compile a list of the steps taken to reach our current point. I tried to include all the important processes that were used to solve each puzzle or decipher rune pages. I am hoping that with this list, someone will look back on what has been done, have an idea, and be able to solve the puzzle(s) on which we are currently stuck.

## **Tools to decrypt the words written in runes**

To decrypt all the pages you can get a tool written in C from elbarto@reborn.com . It's very useful and his new version is completely fast. In less that one second it compares the combination of letters with a complete english dictionary to find any possible match. When you've found them, you can decrypt everything. (not just cicada)

If you know any letters, you can search for those words: if you have "xyzww" and you know that w="S", you write "xyzSS" and the program finds any word written that way, for example: abyss, bless, bliss, chess, class, cross, dress, glass, grass, guess....

Anyway just write him and ask for the **DECRYPTIONIST 2.0**

## Update

There are 58 pages in total, labled 0-57. 57 is the most accurate integer that can be squared to reach a number closest to 3301. It cannot be a coincidence.

This leads me to believe that the page number is extremely relevant to solving the next stage of this puzzle. Seeing as page 57 is unencrypted, I believe that we are looking for an encryption where the page number (x) can be substituted with 57 (or 58) to equal 0, since the 57th (or possibly 58th if you count the number of pictures) runic page is unencrypted.

Calculating the number 3301 in Base58 gives "ur," which is a Sumerian city. This supports the idea of Cuneiform, and also adds the possibility of x being 58.

I will continue to post my findings.

**-Near**

If you add up all the numbers of the pages in the runes you get 0+1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30+31+32+33+34+35+36+37+38+39+40+41+42+43+44+45+46+47+48+49+50+51+52+53+54+55+56+57 = 1653 which is the 57th triangular number, if you add up its numbers then u get 15.

If you add up the numbers in the runes individually like this 0+1+2+3+4+5+6+7+8+9+1+0+1+1+1+2+1+3+1+4+1+5+1+6+1+7+1+8+1+9+2+0+2+1+2+2+2+3+2+4+2+5+2+6+2+7+2+8+2+9+3+0+3+1+3+2+3+3+3+4+3+5+3+6+3+7+3+8+3+9+4+0+4+1+4+2+4+3+4+4+4+5+4+6+4+7+4+8+4+9+5+0+5+1+5+2+5+3+5+4+5+5+5+6+5+7 = 393 which if u add up its numbers u get 15 too. If you reverse 393 u get 393 which is not prime, but it is only divisible by 11 and 53 which are both prime (without counting 1 and itself).32 is the closest number that if you square it you get almost 1033, and 57 is the closest to 3301, which is the total number of names of pages. Also if you reverse 1653 and 393 and do 3561 - 393 you get 3168 which is 133 away from 3301, which is 1033 without counting its 0, and their two factors are prime, 7 and 19, 7+19 = 26. 133 is also a polygonal number of octagonal(7). 7 appears both when you add up the numbers in 3301/1033/133 and 133 in its polygonal. The 133rd prime is 751 which I really like because its digits appear almost everywhere in their relationships with other numbers, the 751 prime is 5701, the octal of 751 is 1357 (going up 2 by turn and all primes except 1), its duodecimal is 527 (close tho).

32 + 26 = 58 which is the total amount of runes. 32 is a hamming number and its prime factorization is 2*2*2*2*2. The 32nd prime number is 131, which adds up to 5, same as 32. The factors can be found by multiplying the first factor (1) by 2 until you get to 32 (1, 2, 4, 8, 16, 32). If you reverse 32 you get 23 which is also a prime, the 9th prime. The base8 of 26 is 32 which I think isn't a coincidence. A funny thing about 26 and 101 (the 26th prime) is that in 26 between the base8 and the base12 have a difference of 10 (octal 32, duodecimal 22) and 101 has a difference of 20 between the base12 and the base16 (duodecimal 85, hexadecimal 65). Also since 32 is the closest to 1033 in squaring there could be something, but 32 squared is 1024 which if you add its numbers you get 7, same as 1033 and 3301.

From this I think it is aiming at page 32 and maybe 26 or something like that. And by the way in this titanpad https://titanpad.com/vFCy7T5p0O with the runes and its transcriptions in a few pages there are

(13) at the end or in the middle, the pages with that are 26, 32, 56, 3 (page number 3 has it 3 times), 53, 54. Also in page 32 there is a blurry tree which then only appears in page 55, but in 55 only appears the outline and in 32 it is the interior and blurry. Interesting fact about 32 + 26, it is equal to 58 but if you add 3+2 which is 5 and put it before 2+6 which is 8 you get the same answer which is 58, which is the total amount of pages.

And I forgot to say that in the bible the Genesis 32:26 is "And he said, Let me go, for the day breaks. And he said, I will not let you go, except you bless me." which has 101 characters (the 26th prime) and 23 words (32 reversed), I think that might not just be a coincidence and that it might also be pointing at pages 32 and 26.

Also there are 32 letters in the icelandic runes (see https://en.wikipedia.org/wiki/Icelandic_orthography) and there are also 26 letters in the alphabet, I don´t think this is a coincidence either. When Q, V and X are excluded, there are 32 letters in the Polish alphabet too (https://en.wikipedia.org/wiki/Polish_alphabet) maybe this is just to decipher the runes in the pages or something.

-Pabster

I want to add to the Pabster's edit that 32th page is linked to the 2016 puzzle image, both contain the tree.

-krzyswit2

--

Nothing new for long time. I guess it is over this time.

- These are just ideas.
- This is regarding the amount and number of pages of runes.
- 58 pages named 0-57.
- 3301/57 = 57.9122807018 which makes it the closest to its root
- 1033/32 = 32.28125 which also makes it the closest root
- Maybe something to do with pg 32?
- 5 + 8 = 13
- 3 + 2 = 5
- 5 + 7 = 12
- All add up to 30
- Maybe something?
- The factors of 57 are 3 and 19, both primes.
- Factors of 32 are 2, 4, 8 and 16. Nothing special I think.
- 3 + 19 = 22
- 2 + 4 + 8 + 16 = 30
- 30 + 30 (from the above section) - 22 = 38
- 3 + 8 = 11 prime
- 1 + 1 = 2 also prime
- Maybe something?
- Any ideas or do you think this isn't anything, just add up to this or dismiss it.
- Tnx

## Pages Loaded with binary outguess data

There is quite a puzzling fact that I havent seen mentioned anywhere that is why I thought I would write about it in here:

It seems that so far any outguessed data was quickly dismissed as random garbage on the last 58 pages. However, if maybe garbage, it does not seem to be that random at all.

The 15 pages that produce outguess data wih no key (1 5 27 41 42 43 44 45 46 47 48 49 53 54 55) all produce the same length of data namely 58152 bits of data.

But is even weirder:

- Every stream of extracted data share identical headers of and footers....

Here is a link to the base64 converted data for each loaded page

https://titanpad.com/FHkyEpCDBr

Honestly, could that really be a coincidence?

aobara

Also note that three of the four 'A Koan' pages share the same outguess output of 58152 bits of data:

http://uncovering-cicada.wikia.com/wiki/CICADA_3301_2014_PUZZLE_FACTS_PART_6

An interesting property of the number 58152:

If you add up the digits:

5 + 8 + 1 + 5 + 2 = 21.

The factors of 21 are 3 and 7. 21 is the 7th Fibonacci#.

Now let's assume 21 is a base 60 number. (Using the Babylonian reference) Then 21 is equal to 121 in base 10.

The sum of the three divisors for 121 is 133.

1 + 3 + 3 = 7 and 133 and it's reverse 331 happen to be the header tags for the source code of the 0-57 pages.

The value of the word "Blake" = 311, who was the artist of the onion 1 collage.

I don't think it's a coincidence.

It definitely isn't a coincidence. In the iso file of 2013 if you ran a few files when u cracked the root password it would look very strange. It was encoded language. In it 3301 looked like 33(a block)1. All 0's were blocks. Also the twitter account looked more like this, @12315(block)7(block)51321, it is an 11 letter polly something and it is prime. Also there has to be an equation to get from 12315 to 7. Anyways 12315 is 51321 reversed. Also, 2013 is prime, and the picture was posted the 5th prime, and it was the second year 2 prime, so OK very smart for not to notice that. so back to the beginning, 3301 in the iso root hacked and file ran is 33(block)1 and 1033 is 1(block)33 lets say its 113 and 331 all equal seven, which is prime. So now lets just get our brains wired up and start thinking out of the box, because right now I think we are not only making cicada 3301 think that we have failed because you are letting others do the work but also because you aren't thinking as they expect us to. They are looking for originals, people who don't follow, people who aren't followers or copycats or snitches, people who won't do something till they get it right, but do it till they don't get it wrong, people who will not give up, even when other people think they're gonna fail, people who will keep trying no matter the obstacles or difficulties, people who don't follow the rules, people who won't let others stop them from getting to the end, people who will always ask why, people who won't do what you tell them to, who have imagination, people who make their own style, people who are different, people who like learning, people who seek knowledge, people who want to know what they don't know, people who expect the unexpected, people who are unique, one of a kind and especially smart. The problem is that these people are becoming extinct. I haven't finished 2014 and I will work solo, and I will finish it no matter in how much time, I will finish it, alone.

-13 year old kid IQ of over 150, hacker, learning astrophysics currently, white hat hacker to help websites, and works solo, alone.

## Page 57 QR Scan

<a href="tel:0421812877725">0421812877725</a>. (scanned from mayfly, most likely redlaser glitch)

digits are most likely glitch with red laser. Saved just in case. cicada code

You are not the first one to think that, I also thought that but actually not, by the way, Jens, if ur reading this I got you. U r behind me right now, I went past that some time ago and keep on trying and never give up.:)

By the way 884 people are also in front of you so keep going and try seeing what u can do by yourself. You will get surprised with your own capabilities.

-13 year old kid IQ of over 150, hacker, learning astrophysics currently, white hat hacker to help websites, and works solo, alone.

## Regarding pages 49, 50, and 51...

*Note: I'm new here. I just noticed a few things when reading through this. I hope it can help.*

"Where 4F corresponds to 255": RGB color values range from 0-255. Also mentioned that 4F is maximum value seen in the pages. Could it be reference to colors

--A note on this. If 255 refers to the RGB color system, 4F is equal to 79 in this system. 79 is a prime number. - n3tn0

Also, sexagesimal number systems were developed by the Babylonians - this is closely related to 360 days/year. If I counted correctly, the 255th day in a non-leap year is October 13th. Leap years it is October 14th. Does this have anything to do with it?

*I didn't see this covered anywhere, so I put it here. Should this be a comment? I dunno. -Gopher*

## Final page possible clue?

I haven't been following this for long but I thought about the possibility that the final page might contain important information so I opened it in notepad. I'm sorry if it's not much but I found a copyright in it and am wondering if it could potentialy be a clue. It said "copyright Artifex Software" so maybe they set it up or something.

Artifex Software sites:

http://www.artifex.com/ http://www.ghostscript.com/ http://smartoffice.artifex.com/ http://www.mupdf.com/

I think that Cicada 3301 used GhostScript, but don't know why. Sorry, I'm new

## Regarding 3301 referring to Babylon and Ur

After some research I noticed that the characters from the rune pages looked strikingly like Babylonian text. I'll look into that and see if I can decrypt something from the document. Wish me luck. -Raspberry

## **Tools to decrypt the words written in runes**

To decrypt all the pages you can get a tool written in C from elbarto@reborn.com . It's very useful and his new version is completely fast. In less that one second it compares the combination of letters with a complete english dictionary to find any possible match. When you've found them, you can decrypt everything. (not just cicada)

If you know any letters, you can search for those words: if you have "xyzww" and you know that w="S", you write "xyzSS" and the program finds any word written that way, for example: abyss, bless, bliss, chess, class, cross, dress, glass, grass, guess....

Anyway just write him and ask for the **DECRYPTIONIST 2.0**